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Offline ninjaclone09

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374591#msg374591
« Reply #156 on: August 02, 2011, 02:06:55 am »


I don't really get how this QI thing works much, but I'm pretty sure that the QI isn't 5.


First of all, due to this quote:



QI REPORT

Deck information:
Cards = 30
Total Cost of Cards = 72
Total Cost of abilities = 12
Number of Pillars = 11

QI
Your QI is 7.315 which is means you have too few pillars.

Fix:
Remove 2 copies of Golden Dragon.
Take 2 copies of Light Pillar.

This will change your QI to 5.152.



Assuming this calculation is correct, you calculate the QI by doing this:
Add the total cost of the cards and the total ability costs, then subtract it by the number of pillars and put a decimal after the first number
72 + 12 = 74 - 11 = 73 then put a decimal and its 7.3. And somethnig that has to do with the number of cards changes it to 7.315. not a big difference.



So lets get back to the death grinder.
Cost of all of the cards:
6 Bone dragons - 10 quanta each - 60 quanta
6 Poisons - 1 quanta each - 6 quanta
3 Plagues - 4 quanta each - 12 quanta

No ability costs. Add up the cost of all the cards:
60 + 6 = 66
66 + 12 = 78

Subtract it by the number of pillars
78 - 15 = 63.

Put in the decimal
63 --- 6.3

Add .015(since there are 30 cards)
Final answer - 6.315


So the QI is 6.315, not 5. I'm probably wrong, and if I am, please help me :) thanks

Offline willng3

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374594#msg374594
« Reply #157 on: August 02, 2011, 02:22:13 am »
Um.  That's not right.

For the Death grinder:
(Bone Dragon = 10 :death) x 6 =  60
(Poison = 1 :death) x 6 = 6
(Plague = 4 :death) x 3 = 12

Total of card costs:  60 + 6 + 12 = 78 :death.

There are no abilities so that part can be ignored.  So your math up until this portion is fine.  But you're doing a few things incorrectly after this point.  Firstly, you do not subtract the number of pillars from the total cost of cards + abilities.  You divide the total cost of cards + abilities by the number of pillars in your deck.  There is also nothing about simply moving the decimal here.

So since you have 15 Pillars here you now proceed with 78/15 = 5.2 ~ 5
So while it's not exactly 5, it's pretty darn close.
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Offline pikachufan2164

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374595#msg374595
« Reply #158 on: August 02, 2011, 02:33:02 am »
Actually,

Bone Dragon (6×10 :death = 60)
Poison (6×1 :death = 6)
Plague (4×3 :death = 12)

Total: 60+6+12 = 78 :death

Assuming mark is Death,

Pillars (15)
Mark (1)

Total: 15+1=16

QI = 78/16 = 4.875
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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374597#msg374597
« Reply #159 on: August 02, 2011, 02:36:42 am »
^While it would be fairly obvious that the Mark should be :death, nowhere in that picture is it stated or posted that that is the Mark given or else I would have included it, hence why it's being assumed as such in the first post and in the calculations that follow.
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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374609#msg374609
« Reply #160 on: August 02, 2011, 04:15:01 am »
Question:
For decks with costs and gains that can vary wildly - dissipation shield, rewound skeletons - how would QI be calculated?


I would be willing to write the framework for the QI calculator. I'll also write it to look up a bunch of files with the card data in plain-text XML, as I really don't relish the idea of typing in the individual costs of every card in the game. Someone else would have to type the costs and quanta production of every card themselves after I'm finished, but it would also mean I could die ditch the project and it could be updated without me.

Offline ninjaclone09

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg374637#msg374637
« Reply #161 on: August 02, 2011, 06:59:37 am »
Ok, now that i have this straight:

SAMPLE DECK:
20x aether pillar
2x parallel universe
4x dimensional shield
4x silence
5x turqoise nymph



Cost:
2x parallel universe = 14 quanta
4x dimensional shield = 24 quanta
4x silence = 12 quanta
5x turqoise nymph = 40 quanta

14 + 24 = 38
12 + 40 = 52
52 + 38 = 90

Ability Cost:
5x turqoise nymph ability; immortality:
90 + 15 = 105

105 divided by 20 = 5.25

QI = 5.25
:D

Offline 10 men

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375433#msg375433
« Reply #162 on: August 04, 2011, 11:21:37 am »
I have a thought experiment for QI enthusiasts:

We're playing a redux version of Elements, normal rules but simplified a bit: There is no maximum deck size, no maximum number of cards you can have in a deck (i.e. you can play any number of non-pillar cards too), no maximum HP (you still start with 100 of course, but if you heal 20 you will go to 120), and no maximum amount of permanents and creatures that can be on the field. Other than that all rules are the same. Ok?

Ok. First question: What's the correct pillar ratio for an unupgraded Anubis deck. The only cards that are allowed are Time Factories and Anubis (but any number of either).

Second question: You know the following about your opponent: He will play an arbitrarily large deck (deckout is not an option) of 80% Shards of Gratitude and 20% Quantum Towers. What's the best build now?

Have fun thinking about it! ;)
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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375467#msg375467
« Reply #163 on: August 04, 2011, 02:52:46 pm »
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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375478#msg375478
« Reply #164 on: August 04, 2011, 03:16:24 pm »

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375483#msg375483
« Reply #165 on: August 04, 2011, 03:28:30 pm »
Then I would like to Thank You. I use it quite often.
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Offline Pineapple

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375485#msg375485
« Reply #166 on: August 04, 2011, 03:35:11 pm »
I have a thought experiment for QI enthusiasts:

We're playing a redux version of Elements, normal rules but simplified a bit: There is no maximum deck size, no maximum number of cards you can have in a deck (i.e. you can play any number of non-pillar cards too), no maximum HP (you still start with 100 of course, but if you heal 20 you will go to 120), and no maximum amount of permanents and creatures that can be on the field. Other than that all rules are the same. Ok?

Ok. First question: What's the correct pillar ratio for an unupgraded Anubis deck. The only cards that are allowed are Time Factories and Anubis (but any number of either).

Second question: You know the following about your opponent: He will play an arbitrarily large deck (deckout is not an option) of 80% Shards of Gratitude and 20% Quantum Towers. What's the best build now?

Have fun thinking about it! ;)
1. According to 5QI, any totalcost / totalpillar = 5.
T = number of towers, A = number of anubes.
(8A-T)/T = 5
8A - T = 5T
8T = 6T
A/T = 6/8 = 3/4

Therefore, according to 5QI, it would either be 13 Anubes to 17 Towers (least amount of cards) or 15 Anubes and 20 Towers (perfect ratio). If the 30 card rule wasn't in place, it would be as many cards as needed to kill the opponent before decking out. This is because, although according to QI, any deck with a 3 to 4 ratio would be equally efficient, we all know that QI doesn't take drawing 1 card per turn into account. The only way to make good use of good QI is to have the perfect draw; too many creatures and you won't have enough quanta, too many pillars and you'll have less than satisfactory damage. Doubling the deck would only increase the chances of you not getting a perfect draw.

2. To maximize your win chance against the deck, you know that it has an average of drawing 4 SoGs every 5 turns, which means that you have to play 4 anubes every 5 turns to match the damage. Therefore, you can only use the smallest deck (since increasing to the Anubis to Tower ratio to 4:5 won't increase the Anubes you play, only the ones stuck in your hand) and hope that it has Tower-heavy draws while you have perfect draws.

--

P.S. Don't kill me for butchering the plural form of "Anubis", whatever it is.

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Re: Using Quanta Index to determine the optimal number of Pillars in a deck https://elementscommunity.org/forum/index.php?topic=5676.msg375812#msg375812
« Reply #167 on: August 05, 2011, 11:31:41 am »
2. To maximize your win chance against the deck, you know that it has an average of drawing 4 SoGs every 5 turns, which means that you have to play 4 anubes every 5 turns to match the damage. Therefore, you can only use the smallest deck (since increasing to the Anubis to Tower ratio to 4:5 won't increase the Anubes you play, only the ones stuck in your hand) and hope that it has Tower-heavy draws while you have perfect draws.
Hehe. You can actually make a deck that has 100% winrate against it. (You're reasoning is good but you've made one mistake.)
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