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Offline russianspy1234Topic starter

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Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017312#msg1017312
« on: November 23, 2012, 09:15:21 pm »
NAME:
Velociraptor
ELEMENT:
Time
COST:
4 :time
TYPE:
Creature
ATK|HP:
1 | 3
TEXT:
Velociraptor gets +1 | +0 for each other Velociraptor in the same rank.
NAME:
Velociraptor
ELEMENT:
Time
COST:
4 :time
TYPE:
Creature
ATK|HP:
2 | 4
TEXT:
Velociraptor gets +1 | +0 for each other Velociraptor in the same rank.

ART:
http://www.sxc.hu/photo/442605
IDEA:
russianspy1234
NOTES:
hopefully the same rank limitation is enough to counteract the fractal problem, though I'm afraid I might have taken it into forced combo territory (with

either fractal or mitosis)
SERIES:

« Last Edit: March 02, 2013, 06:11:00 am by Annele »
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Offline EmeraldTiger

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017327#msg1017327
« Reply #1 on: November 23, 2012, 09:59:06 pm »
If it were me doing a card with this name, I would work a Pun into it. Velociraptor and Velocity = a :time/ :gravity duo
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Offline OldTrees

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017329#msg1017329
« Reply #2 on: November 23, 2012, 10:12:07 pm »
How to balance this card:

A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play

(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
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Offline russianspy1234Topic starter

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017353#msg1017353
« Reply #3 on: November 24, 2012, 12:30:15 am »
If it were me doing a card with this name, I would work a Pun into it. Velociraptor and Velocity = a :time/ :gravity duo

heh yeah that might have been good, but time already has a creature that uses :gravity

How to balance this card:

A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play

(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
not quite sure what i'm supposed to do with these formulas...
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Offline OldTrees

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017378#msg1017378
« Reply #4 on: November 24, 2012, 03:37:26 am »
How to balance this card:

A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play

(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
not quite sure what i'm supposed to do with these formulas...
Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)
Then you can check to see if that casting cost results in balance with Total Attack / Total Cost.
"It is common sense to listen to the wisdom of the wise. The wise are marked by their readiness to listen to the wisdom of the fool."
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Offline russianspy1234Topic starter

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017498#msg1017498
« Reply #5 on: November 24, 2012, 09:30:23 pm »
How to balance this card:

A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play

(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
not quite sure what i'm supposed to do with these formulas...
Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)
Then you can check to see if that casting cost results in balance with Total Attack / Total Cost.
so for the first one, id guess an average of 3, and have 4*3/12=1?
still wouldnt know how to do the other two but.. well its same rank, and should easily hit the max amount in most cases so 7*6 / 4*6+ (cost of mitosis? so 5?) so its 42/28=1.5  but i've seen you factor in (1 card) or such in the cost on other threads...
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Offline OldTrees

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017536#msg1017536
« Reply #6 on: November 25, 2012, 12:19:25 am »
How to balance this card:

A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play

(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
not quite sure what i'm supposed to do with these formulas...
Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)
Then you can check to see if that casting cost results in balance with Total Attack / Total Cost.
so for the first one, id guess an average of 3, and have 4*3/12=1?
still wouldnt know how to do the other two but.. well its same rank, and should easily hit the max amount in most cases so 7*6 / 4*6+ (cost of mitosis? so 5?) so its 42/28=1.5  but i've seen you factor in (1 card) or such in the cost on other threads...
It looks like I misread the card. Since it doesn't count itself it would be (X)(X)/(4X).
Mitosis would cost 5+1(duo)+2(extra card)
So with your estimates it would be:
No support: 3*3/4*3=3/4=0.75
Mitosis: 6*6/(4*6+8)=36/40=0.90
These are fairly close.
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Offline OdinVanguard

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Re: Velociraptor | Velociraptor https://elementscommunity.org/forum/index.php?topic=44812.msg1017926#msg1017926
« Reply #7 on: November 26, 2012, 11:45:49 pm »
It looks like I misread the card. Since it doesn't count itself it would be (X)(X)/(4X).
Mitosis would cost 5+1(duo)+2(extra card)
So with your estimates it would be:
No support: 3*3/4*3=3/4=0.75
Mitosis: 6*6/(4*6+8)=36/40=0.90
These are fairly close.
Just thought I should point out that the top and bottom row hold 8 creatures unlike the middle which holds 7.
So for those we get
Mitosis: 7*6/(4*7+8) = 1.16
... Not a huge difference, but it does extend past the 1 to 1 threshold. Of course, that requires extending your creatures to the top and bottom rows which is a tricky feat in and of itself.

Still, the rank limitation and cost should be sufficient to limit abuse with fractal and mitosis...

It occurs to me that flooding is a potent counter... On the other hand, if this card could survive flooding, the combo would be very vicious. Just thought I'd throw that out there for anyone looking for a card idea.
« Last Edit: November 26, 2012, 11:52:16 pm by OdinVanguard »
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