(http://img.photobucket.com/albums/v241/russianspy1234/ros/velociraptor.png) | (http://img.photobucket.com/albums/v241/russianspy1234/ros/velociraptoru.png) | ||||||||||||||||||||||||
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If it were me doing a card with this name, I would work a Pun into it. Velociraptor and Velocity = a :time/ :gravity duo
How to balance this card:not quite sure what i'm supposed to do with these formulas...
A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play
(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)How to balance this card:not quite sure what i'm supposed to do with these formulas...
A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play
(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
so for the first one, id guess an average of 3, and have 4*3/12=1?Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)How to balance this card:not quite sure what i'm supposed to do with these formulas...
A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play
(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
Then you can check to see if that casting cost results in balance with Total Attack / Total Cost.
It looks like I misread the card. Since it doesn't count itself it would be (X)(X)/(4X).so for the first one, id guess an average of 3, and have 4*3/12=1?Different casting costs result in different values for X, Y and Z (the average number of copies of the creature in play under different support)How to balance this card:not quite sure what i'm supposed to do with these formulas...
A non fractal/mitosis player would likely have an average of X of these in play
A mitosis player would likely have an average of Y of these in play
A fractal player would likely have an average of Z of these in play
(Attack)(Quantity)/(Cost)
(X+1)(X)/(4X)
(Y+1)(Y)/(4Y+Mitosis)
(Z+1)(Z)/(4Z+Fractals)
Then you can check to see if that casting cost results in balance with Total Attack / Total Cost.
still wouldnt know how to do the other two but.. well its same rank, and should easily hit the max amount in most cases so 7*6 / 4*6+ (cost of mitosis? so 5?) so its 42/28=1.5 but i've seen you factor in (1 card) or such in the cost on other threads...
It looks like I misread the card. Since it doesn't count itself it would be (X)(X)/(4X).Just thought I should point out that the top and bottom row hold 8 creatures unlike the middle which holds 7.
Mitosis would cost 5+1(duo)+2(extra card)
So with your estimates it would be:
No support: 3*3/4*3=3/4=0.75
Mitosis: 6*6/(4*6+8)=36/40=0.90
These are fairly close.