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Offline JenkarTopic starter

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Building > https://elementscommunity.org/forum/index.php?topic=48618.msg1061533#msg1061533
« on: April 19, 2013, 09:46:31 am »
Idk if this would work.
Say, you want to compare a & b. That is equivalent to getting the max of a and b (once you know which one is bigger, you know which one is smaller).

Since lim (n=>infinity) n-root(abs(a)^n+abs(b)^n) = max(abs(a),abs(b)), does this give a comparing tool for positive reals?
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Offline Fireleaf

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Re: Building > https://elementscommunity.org/forum/index.php?topic=48618.msg1061537#msg1061537
« Reply #1 on: April 19, 2013, 10:41:10 am »
I'm inclined to say that it might, but you have to make sure that n is big enough and your rounding program smart enough that you don't get a situation where 15.9999 is the max of 12 and 16 for example.
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Offline russianspy1234

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Re: Building > https://elementscommunity.org/forum/index.php?topic=48618.msg1061569#msg1061569
« Reply #2 on: April 19, 2013, 01:04:20 pm »
the behavior wont be identical for a==b. not sure for the general case, it's been a while.
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Offline Furby

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Re: Building > https://elementscommunity.org/forum/index.php?topic=48618.msg1063739#msg1063739
« Reply #3 on: April 25, 2013, 05:02:18 pm »
Both will be the same asumming both a and b are both 0 and/or both <1.

 

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