Graph this!

[Toimu13]

I should be studying, but I'm here.  So I thought I could do both!  I'm not trying to get others to do my work either.

25x^2 + 9y^2 −100x + 54y − 44 = 0

Hint: I'm in precal.

[ddevans96]

I should be studying, but I'm here.  So I thought I could do both!  I'm not trying to get others to do my work either.

25x^2 + 9y^2 −100x + 54y − 44 = 0

Hint: I'm in precal.

You can use superscript for the exponents, you know

Anyways....I'll try this, but I'm only in Algebra II, so I might fail

[Demagog]

It's an ellipse. ((x-2)^2)/9 + ((y+3)^2)/25 = 1

The center is at (2,-3), a = 5 and b = 3. Doubt I have to go further.

Edit: Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

[Toimu13]

It's an ellipse. ((x-2)^2)/9 + ((y+3)^2)/25 = 1

The center is at (2,-3), a = 5 and b = 3. Doubt I have to go further.

Nope, but I need a few extra things (easy) things.

c = 4
eccentricity = 4/5
foci = (2,1) and (2,-7)

Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

Once I finish my homework I'll give it a shot.

[Bloodshadow]

Try this: find the implicit relation that describes the derivative of the unit circle. Hint: the highest degree of the relation is 4, and its graph looks somewhat like an hourglass.

No, implicit differentiation won't work; all you'll get is dy/dx = -x/y, a differential equation with no ways to graph. I want something only in terms of x and y.

Edit: Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

Uh... A parabola? All quadratic functions are parabolas. Isn't that a bit too easy, or is it a trick question?

[Glitch]

Edit: Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

Hmm....

Well, it's only one variable, so it's a parabola.  A=2, B =-1, C=0

Sqr(B^2-4AC)
Sqr(1-0)
Sqr(1)
1

Rational number, it's foilable.

(X+0)(2x-1)

So it's a parabola with 0s of the origin and 1/2.  It's vertex is at (1/4, -1/8).  I don't remember how the weird focal axis thing works... but whatever.  That's one of the answers you'll accept, right?

[Toimu13]

A parabola facing up with a vertex of (1/4,-1/8).

I used Vertex = (-b/2a , f(-b/2a))

-1/2*2 = 1/4

f(1/4) = 2(1/4)^2 - 1/4 = -1/8

Still doing my homework

[icecoldbro]

i relly have to stop sleeping in class after an all nighet playing session i sriously dont get anything on this topic

[Demagog]

Edit: Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

Hmm....

Well, it's only one variable, so it's a parabola.  A=2, B =-1, C=0

Sqr(B^2-4AC)
Sqr(1-0)
Sqr(1)
1

Rational number, it's foilable.

(X+0)(2x-1)

So it's a parabola with 0s of the origin and 1/2.  It's vertex is at (1/4, -1/8).  I don't remember how the weird focal axis thing works... but whatever.  That's one of the answers you'll accept, right?

I guess the title confused you. I meant what does the equation describe. It's a real life thing. The graph doesn't matter.

[Toimu13]

I guess the title confused you. I meant what does the equation describe. It's a real life thing. The graph doesn't matter.

Boobies?

[Demagog]

Edit: Here's one for you. The function f(x)=2x^2-x describes what? There are two answers I'll accept.

Hmm....

Well, it's only one variable, so it's a parabola.  A=2, B =-1, C=0

Sqr(B^2-4AC)
Sqr(1-0)
Sqr(1)
1

Rational number, it's foilable.

(X+0)(2x-1)

So it's a parabola with 0s of the origin and 1/2.  It's vertex is at (1/4, -1/4).  I don't remember how the weird focal axis thing works... but whatever.  That's one of the answers you'll accept, right?

A parabola facing up with a vertex of (1/4,-1/8).

I used Vertex = (-b/2a , f(-b/2a))

-1/2*2 = 1/4

f(1/4) = 2(1/4)^2 - 1/4 = -1/8

Did I mess up?

I don't feel like finding the x or y intercepts, still doing my homework

I guess the title confused you. I meant what does the equation describe. It's a real life thing. The graph doesn't matter.

Boobies?

If only... if only...

[Toimu13]

I'm having trouble with this one:

Determine the number of points of intersection for the system.

x + y = 8
Is a line.  (8,0) and (0,8)

(x^2/4) - (y^2/4) = 1
I want to say is a Hyperbola, but can a=b ?  And can I change it to:

x - y = 2

If I can, then can I say:

x - y - 2 = x + y - 8

But then y = 2 and I don't have an x.

I guess the title confused you. I meant what does the equation describe. It's a real life thing. The graph doesn't matter.

Boobies?

If only... if only...

I'm lost, even googled it.