Graph this!

[Demagog]

If I remember correctly, to do this problem you need to use substitution. So in the first equation, move the x over to get y=8-x. Then plug that equation into the other one, meaning you replace all y's in the second equation with 8-x. Then you solve for x in the second equation. Once you have the x, you can plug that into the first equation to find the y value.

And if all else fails, graph both equations. The thing to watch out for with linear equations and hyperbolas is that the linear equation might describe one of the asymptotes of the hyperbola, meaning you wouldn't have an intersection.

And you simplified that second equation wrong when you took the square root of both sides. I don't think you can do it like that.

Also, the answers I was looking for were perfect numbers and hexagonal numbers.

[Toimu13]

If I remember correctly, to do this problem you need to use substitution. So in the first equation, move the x over to get y=8-x. Then plug that equation into the other one, meaning you replace all y's in the second equation with 8-x. Then you solve for x in the second equation. Once you have the x, you can plug that into the first equation to find the y value.

And if all else fails, graph both equations. The thing to watch out for with linear equations and hyperbolas is that the linear equation might describe one of the asymptotes of the hyperbola, meaning you wouldn't have an intersection.

And you simplified that second equation wrong when you took the square root of both sides. I don't think you can do it like that.

Also, the answers I was looking for were perfect numbers and hexagonal numbers.

I was going to say they are two lines, but IDK now.  The problem with trying to graph it is I don't know what the second one is, and I don't have a graphing calculator that can do 2 variables.  Going to try substitution now.  Thanks for all the help!

BTW, I haven't learned about hexagonal numbers yet.

[Demagog]

Type your equation in here: http://www.wolframalpha.com/

[7_Deadly_Sins]

I hope precal isn't hard I'm taking it next semister.

[Kurohami]

What's ellipse? Is it when you graph something divided by 0? I suck at math, so don't laugh at me.

[Korugar]

Well, an ellipse is like an elongated circle, if that's what you're asking. Basically an oval, but for some reason it has a different name in mathematics.

[Kurohami]

Well, an ellipse is like an elongated circle, if that's what you're asking. Basically an oval, but for some reason it has a different name in mathematics.

Oh, ok, so what is the pattern that forms when you graph something divided by 0 called?

[Korugar]

That's...a good question that I don't have an answer to I don't know if I'm not advanced enough, or if I'm just having a mental block, but I've got no idea.

[Kurohami]

My teacher told me it's a circle that explodes inward to infinity. Don't know what that means.

[Demagog]

You can't divide by zero lol... there is no graph. Ask your teacher to show you where they got this information.

[Kurohami]

You can't divide by zero lol... there is no graph. Ask your teacher to show you where they got this information.

Lolz, my teacher tell us lots of things, but he never cites his information.

[Bloodshadow]

Oh, ok, so what is the pattern that forms when you graph something divided by 0 called?

Uh... I dunno... Degenerate conic sections? Well, that happens when you have something EQUAL to zero (e.g. a degenerate circle = circle with radius 0 = a point). You don't really get anything when you divide by zero.

My teacher told me it's a circle that explodes inward to infinity. Don't know what that means.

There are three problems with that statement:
1. Circles don't explode; they are closed curves and have no asymptotes.
2. Exploding inward is called imploding.
3. If you implode inward, you don't go to infinity, you go to zero.

So I have no idea what your teacher was talking about.