Last cards fail?

[Captain Scibra]

Just for kicks, you can figure out what the percent chance was that specific cards in your deck were all the last cards:

100%*C!*(T-C)!
           T!

where T is total cards in the deck, and C is the number of the specific cards.

Example:

CCYB has 2 Lava Destroyers.  The chance that they are the last 2 cards in you deck is 100*2!*(35-2)!/35!, which if worked out on paper, you get the fraction 2/(34*35) or 2/1190, which is 0.0016806722689075630252100840336134%

[teffy]

you get the fraction 2/(34*35) or 2/1190, which is 0.0016806722689075630252100840336134%

The fraction 2/1190 is 0.00168... if you write it in percent, you have to multiply it with your 100.  That means the chance is 0.168... % that the last 2 cards of you 35-cards deck are Lava Destroyers.

[Pineapple]

Actually, teffy, the decimal is 0.0000168...
You can see in the formula that they use "100%", and the Malignant uses 100 in his calculations as opposed to 1, so the result is 100 times more than the decimal result, and therefore the percentage.

[Pineapple]

1*C!*(T-C)!/T!

Your last card in your 60-card timebow was the only eternity.

1*1!*(60-1)!/60!
0.01666...
1 and 2/3 percent? Isn't that rather high?

[Captain Scibra]

Well, since it is a single card, you simply use the fraction 1/60.  But yeah, that is the percent.  I found it lol to be able to determine how bad your luck was when someone mentioned that they had 2 lava destroyers as their last 2 cards in CCYB.

teffy is right, I never multiplied it by 100.  So it is actually 0.16806722689075630252100840336134%