Start with x=yx^2=xyx^2-y^2=xy-y^2(x-y)(x+y)=y(x-y)(x-y)(x+y)/(x-y)=y(x-y)/(x-y)x+y=yIf x=1, then y=1, so 1+1=1
QuoteStart with x=yx^2=xyx^2-y^2=xy-y^2(x-y)(x+y)=y(x-y)(x-y)(x+y)/(x-y)=y(x-y)/(x-y)x+y=yIf x=1, then y=1, so 1+1=1If x=y, then y(x-y)/(x-y) is 0/0, or a divide by zero error.Nice try.