Asked in chat, they said resurrecting this thread would be better than making a new one.
One small problem with implosion's set up, unupped entropy dragon only has 10 attack, and you can't mutate into upgraded cards. If the mutant was a crimson dragon, then deja vu costs fire quanta. It still works, but you have to have fire mark, and draw a fourth quanta tower.
Absolute most damage possible first turn (highly derived from implosions kickass work):
You get 8 cards in opening hand.
Oracle grants you a pet.
You have entropy mark.
You draw:
-Regular mutation
-3x quantum tower
-chaos seed
-3x pandemonium
The quantum towers give you nine entropy quanta.
The mutated pet gives you a crimson dragon (12|3), +5 (17). Two entropy quanta spent (7 remaining).
The chaos seed twins the dragon, giving it +5 (22|13), (17 & 22). One entropy quanta spent (6 remaining).
The pandemonium twins both dragons, giving all +5 (22|13 & 27|18), (17 & 22*2 & 27). Two entropy quanta spent (4 remaining).
The pandemonium twins all four dragons, giving all +5 (22|13, 27|18*2, 32|23), (17 & 22*3 & 27*3 & 32).
The pandemonium twins all 8 dragons, giving all +5 (22|13, 27|18*3, 32|23*3, 37|28), (17 & 22*4 & 27*6 & 32*4 & 37).
Total damage = 17 + 22*4 + 27*6 + 32*4 + 37 = 432.
The odds of this happening are as follows:
The odds of drawing exactly three pandemonium, assuming 6 in deck, is 14.520200412614%
The odds of drawing exactly one chaos seed, assuming 6 in deck, is 35.4801061007958%
The odds of drawing exactly one mutation, assuming 6 in deck, is also 35.4801061007958%
The odds of drawing exactly three quantum towers, assuming they make up the rest of the 30 card deck, is 32.2054357436666%
When drawing 8 cards at random from this deck, there are 30*29*28*27*26*25*24*23*22 possible opening hands. The number of successes is difficult to calculate. You need to draw:
1 chaos seed (one success)
AND
one mutation (one success)
AND
three pandemonium (6*5*4 successes)
AND
three quantum pillars (12*11*10 successes).
These cards can come in any order, multiplying the number of successes by the number of orders 8 cards can go in, or 8!, or 40,320. Multiplied by the number of successes due to multiple cards, you get 6,386,688,000 possible successes.
The odds of drawing all eight cards in your opening hand is the second number divided by the first, or 6,386,688,000/5.19177859 × 10^12, or 00.123015415%. Not as unlikely as you'd think.
The odds of three consecutive quantum towers giving 9 entropy quanta is 1/12^9, or 00.0000000193806699%.
The odds of getting a successful mutant from mutation is 4/10
AND
The odds of getting a crimson dragon is 1/82
AND
The odds of getting +5 is 1/5
So the total odds of mutating what you need is 4/(10*82*5), or 00.0975609756%
Pandemonium has a total of 14 things it can do. Drain Life, Freeze, Ice Bolt, Fire Bolt, Lobotomize, Reverse Time, Parallel Universe, Gravity Pull, Poison, sniper, lightning, shockwave. It has a 1/14 chance to PU each dragon each time. It needs to PU 15 times. The odds of this are (1/14)^15. There is a 1/5 chance of the attack power getting+5, the odds of this happening 15 times are (1/5)^15. The odds of both of these happening are 2.10634448 × 10^-28, or 00.0000000000000000000000000210634448%
The odds of getting a pet from the oracle are unknown, and will be represented by X.
The odds of mutating a quintessence'd dragon are not factored in. I'll do this when it's not 4 A.M.
The total odds of getting 432 damage first turn are .000000000000000000000000000210634448*.000975609756*.000000000193806699*.00123015415*X, or (4.89929798 × 10^-44)X, or 00.00000000000000000000000000000000000000000489929798%*X
The odds of this are disgustingly low.
Statistically, you should play 2.04110875 × 10^36, or 2,041,108,750,000,000,000,000,000,000,000,000,000 games before this ever happens.
I've shown all my work, feel free to correct me.
