Round 4 - rob77dp vs RootRanger

[RootRanger]

 

[rob77dp]

Un-officially, my records indicate this as the correct solution.

If Submachine can verify Root's attempt is indeed the solution then before I spend my "oh so valuable time" /depress-sarcasm-button on a final round of logic-flow (prior to my next (7th) guess) I would appreciate Submachine reviewing the tie-breakers for who would win if my 7th guess is fully correct.  If Root is OK with the above action request and Sub reveals that I could win with a correct 7th attempt then I'll do my homework and provide a final guess.  Otherwise, if I cannot win with a correct 7th guess then I will forfeit the match to Root.

[Submachine]

rob is right

The code is solved!

Attempts: 7

Now to answer your question, rob, here is the tiebreaker i use:
1.the most attempts were needed,
2.the average of his "result icons" ( and ) was the lowest,
3.had the least amount of icons.

Based on the first, you cannot win if your next answer is not correct.
From the second, I'll assume that your next guess will be the correct guess, otherwise there would be no need to continue. If your next guess is correct, you will have equal number of attempts, so there is no need to take an average. The sum of your result icons are equal, so this tiebreaker doesn't lead us anywhere (5+3+2+3+2+3+1=5+3+3+3+2+1+2=19, correct me if i'm wrong).
Based on the third, Root collected 10  icons. If your next guess is correct, you'll have 12, so yes:

TL;DR: If your next guess is correct, you win, but otherwise you lose.

[rob77dp]

rob is right

The code is solved!

Attempts: 7

Now to answer your question, rob, here is the tiebreaker i use:
1.the most attempts were needed,
2.the average of his "result icons" ( and ) was the lowest,
3.had the least amount of icons.

Based on the first, you cannot win if your next answer is not correct.
From the second, I'll assume that your next guess will be the correct guess, otherwise there would be no need to continue. If your next guess is correct, you will have equal number of attempts, so there is no need to take an average. The sum of your result icons are equal, so this tiebreaker doesn't lead us anywhere (5+3+2+3+2+3+1=5+3+3+3+2+1+2=19, correct me if i'm wrong).
Based on the third, Root collected 10  icons. If your next guess is correct, you'll have 12, so yes:

TL;DR: If your next guess is correct, you win, but otherwise you lose.

Hopefully this does not come across as whining or stalling because that is not my intent with this request.

I request Sub (or Root?) to double-check the reported results of my prior guesses.  I have about 8 pages of logic flow.  It is resulting in no possible combinations... hence my request for a quick double-check of the posted results as I am usually careful enough to not make such an egregious error in my logic as to yield this impossible result.

[RootRanger]

The reported results all look correct to me.

[Submachine]

rob is right

The code is solved!

Attempts: 7

Now to answer your question, rob, here is the tiebreaker i use:
1.the most attempts were needed,
2.the average of his "result icons" ( and ) was the lowest,
3.had the least amount of icons.

Based on the first, you cannot win if your next answer is not correct.
From the second, I'll assume that your next guess will be the correct guess, otherwise there would be no need to continue. If your next guess is correct, you will have equal number of attempts, so there is no need to take an average. The sum of your result icons are equal, so this tiebreaker doesn't lead us anywhere (5+3+2+3+2+3+1=5+3+3+3+2+1+2=19, correct me if i'm wrong).
Based on the third, Root collected 10  icons. If your next guess is correct, you'll have 12, so yes:

TL;DR: If your next guess is correct, you win, but otherwise you lose.

Hopefully this does not come across as whining or stalling because that is not my intent with this request.

I request Sub (or Root?) to double-check the reported results of my prior guesses.  I have about 8 pages of logic flow.  It is resulting in no possible combinations... hence my request for a quick double-check of the posted results as I am usually careful enough to not make such an egregious error in my logic as to yield this impossible result.

I understand that it's quite a big pressure, so I not only checked, but also ran it through the process of elimination and i got to 3 possible results. That means you have a 33% chance to guess it right if you go through the same process. Hopefully that will give you enough incentive to continue.

[Submachine]

This is getting longer than I wanted. I give rob some time to make his move, but after that I'll start the final round.

To send in the next attempt, rob has:
no time left.

[rob77dp]

#6 -

Result: 

#7 -
For all the marbles in this matchup!  I quite working through my re-do of logic after finding five possible solutions...  I chose this one randomly from the group of five!
:p

Either way, great match Root... and apologies for my dragging it out a bit.  I just cannot find the free time for elements-related fun as I used to!  :/

[Submachine]

Five? O_o I could only find 3, lol.
And if it was random, Lady Fortuna was really with you today.

#7 -
For all the marbles in this matchup!  I quite working through my re-do of logic after finding five possible solutions...  I chose this one randomly from the group of five!
:p

Either way, great match Root... and apologies for my dragging it out a bit.  I just cannot find the free time for elements-related fun as I used to!  :/

The code is solved!

Attempts: 7
And you posted just in time. Only some hours left.

[rob77dp]

Well then, Lady Luck I thank you for this one.  Here I come elk-y!!