Chaos Root | Chaos Root

[zamboza]

NAME: Chaos Root ELEMENT: COST: 5 TYPE: Spell ATK|HP: TEXT: Destroy up to 3 random permanents of enemy	NAME: Chaos Root ELEMENT: COST: 4 TYPE: Spell ATK|HP: TEXT: Destroy up to 3 random permanents of enemy

ART: IDEA: zamboza NOTES: Each pillar counts separately! SERIES:

[Nepycros]

So, it's a random Earthquake that can get rid of weapons, shields, mindgates, empathic bonds, unstable gases, sundials, etc. as well as pillars? No.

[ArtCrusade]

So, it's a random Earthquake that can get rid of weapons, shields, mindgates, empathic bonds, unstable gases, sundials, etc. as well as pillars? No.

Basically, that.

Please think about how your idea works and what it'll do to the current balance. The card advantage caused by EQ is big already, but the advantage THIS card would cause is HUGE. A pillar costs nothing to play it, HGs/weapons/shields/Mindgates ect. do cost quanta.

[zamboza]

If I'll increase it cost by 1, will you be satisfied?

[zamboza]

OK, I thought about cost and results are below.

Lets think that you use 3 deflagrations on random permanents. It'd cost 6 .

Remember it's random, so let's substitute 1 quanta.

You use deflagrations (at most) to destroy shields, weapons or permanents that aren't pillars. This can destroy pillars, so let's substitute another 2 quanta.

As you see, it decrease costs by half, what do you think now?

[ArtCrusade]

So this is like 3 Deflags, which cost 6 This card does the same. but only for 3 This card must actually cost more than 3 Deflags, a lot more. And it's futile to argue like "it randomly destroys permanents", because that's just unimportant. And don't forget Entropy already has a lot of control-cards like Discord, Pandemonium, BE and Antimatter. This card would make Entropy even more off the balance.

So I would suggest a cost like 9|8. Pretty expensive you say? Just about right I say.

[Retribution]

Think of it this way.
3 defrags take up 3 spaces in your deck, instead of 1.
There is also a much less chance you will draw three, instead of, say, one chaos root.

Besides, entropy has butterfly effect already. No need to add more.

[zamboza]

You're both right. You think that it's unnecessary, ArtCrusade, that it destroy random. In that case, you also can argue about Chaos Seed effect, because it can be as well fractal. You haven't thought that it can also destroy 3 pillars? I think that not. So, according to chaos seed, I don't think that it needs changes.

But Retribution is right. I'll change cost by 2.

[RootRanger]

I think Root is way too powerful.

Seriously, it is. It's too powerful early game. If you have 6 of these and a lot of towers, you can completely shut down the opponent. Throw in some devourers and they will be helpless. Sure, explosion costs 1 quanta, but it is one destruction per card. Same with steal. Remember that you only draw one card per turn. When you get that card, will you want to destroy 3 permanents or 1? Also, I don't think entropy fits. Sure it is random and chaotic, but entropy has a lot of control already.

EDIT: Meh, Retribution probably said it better.

[OldTrees]

OK, I thought about cost and results are below.

Lets think that you use 3 deflagrations on random permanents. It'd cost 6 .

Remember it's random, so let's substitute 1 quanta.

You use deflagrations (at most) to destroy shields, weapons or permanents that aren't pillars. This can destroy pillars, so let's substitute another 2 quanta.

As you see, it decrease costs by half, what do you think now?

Lets use this line of thought
3 deflagrations = 3 cards and 6

This is one card so it is easier to draw and can destroy more than an equal number of deflagrations. To underestimate lets call this 4 (Aether for card generation [Mindgate])

Now it is indeed random and has to occur all at once. This means that it will destroy a less valuable 3 than 3 deflagrations. This could be worth -1 quanta.

Changing a duo cost into a mono cost is worth +1 quanta.

Total for Deflag comparision 10 .

Deflag is used for non pillars, this can also act as Earthquake instead
1 earthquake = 1 card and 3

Total for Earthquake comparision 3 .

Now the question is how is it random? Does it count each pillar separately? or just the slots?

Assuming slots there is a 2:1 ratio or greater of non pillars to pillars (i think)
So final underestimation would be (2x10+3)/3=~8 quanta.

[zamboza]

Now the question is how is it random? Does it count each pillar separately? or just the slots?

Each pillar separately. It's why it's cost is so low.

[OldTrees]

Now the question is how is it random? Does it count each pillar separately? or just the slots?

Each pillar separately. It's why it's cost is so low.

If each pillar separately then the ration pillars to no pillars is 3:1 or so (i think)
(3x3+10)/4=5

Sounds right. You should mention in the notes that it counts by pillar and not by stacks.