The sample size of 2000 is high enough. We would get more problems, if p~0, or p~1. But here:
For normal distribution, we often demand : var = sd^2 = n*p* (1-p) > 9. 500,5 >3.
Other formulas which say when I can use normal distribution give similar results.
Using normal distribution for coin toss, and the 3-sigma rule, we get the result:
The chance is ~ 99,73 % , that number blocked creatures / number of creatures is in the intervall [0,5 - 0, 033524 , 0,5+ 0, 033524]
( 0,5 +/- 3/ (2* sqrt(n)) , sqrt (n) = n^(1/2) )
We have 1288 / 2002 ~ 0,643 > 0,533524!
That means, the result above is very very unlikely!
That´s either a wrong measurement, or an algorithm mistake or very very bad luck.
Edit: missed a "3". Mistake corrected.
0,1117*3=0,033524