Entropic Shield | Chaotic Shield

[russianspy1234]

NAME: Entropic Shield ELEMENT: Entropy COST: 6 TYPE: Permanent ATK|HP: TEXT: Shield: Reduce damage by a random amount.	NAME: Chaotic Shield ELEMENT: Entropy COST: 6 TYPE: Permanent ATK|HP: TEXT: Shield: Reduce damage by a random amount.

ART: http://www.sxc.hu/photo/1331805 IDEA: russianspy1234 NOTES: unupped: 0-6 upped: 1-7 probabilities do not have to be even, not sure of balance yet. SERIES:

[Drake_XIV]

Simple and embodies   to a tee.  I like it.  But considering the range and erratic blocking, Maybe make the cost 4 for both?

[furballdn]

0-4 random would average out to be 2. 1-5 averages out to 3. Does a 2|3 damage reduction shield really deserve to cost 6 ?

[russianspy1234]

Simple and embodies   to a tee.  I like it.  But considering the range and erratic blocking, Maybe make the cost 4 for both?

id rather up the range of blocking than dropping cost as entropy already has a "cheap" shield.  yeah comparing to diamond shield it is a little underpowered.

upped the ranges, averages at 3 and 4.5 now.

[furballdn]

WHY? At 6 for an average of 3 dr, this unupped shield is just as powerful as tit shield. Upped, it's 1.5 times as good as tit shield for the same price.

[Drake_XIV]

WHY? At 6 for an average of 3 dr, this unupped shield is just as powerful as tit shield. Upped, it's 1.5 times as good as tit shield for the same price.

But it has the chance to be.  In other cases, if is as good as a lower tier shield.

[russianspy1234]

WHY? At 6 for an average of 3 dr, this unupped shield is just as powerful as tit shield. Upped, it's 1.5 times as good as tit shield for the same price.

in part, because when staring down a field of variable strength creatures, its not unlikely for you to "roll" a 6 on a 1 attack creature and a 1 on a 10 attack creature.  in any case, the numbers can be fudged in development., its the basic idea of random damage reduction i was going after.

[OdinVanguard]

Just my two  , but I would say the unupped should be reduced to 4  to put it in line with the  equivalent. I would also suggest the following probabilities. Based on a bell shaped distribution, e.g. each potential point of reduction treated as a coin flip with a 50% chance of success. The upped version was made using a 7 coins and automatic +1 reduction.

Unupped 0 -> 1.56% 1 -> 9.38% 2 -> 23.44% 3 -> 31.25% 4 -> 23.44% 5 -> 9.38% 6 -> 1.56%

Upped 1 -> 0.78% 2 -> 5.47% 3 -> 16.41% 4 -> 27.34% 5 -> 27.34% 6 -> 16.41% 7 -> 5.47% 8 -> 0.78%

This can easily be adjusted to set the average to any value in the range by adjusting the success rate (like a loaded coin). I.e. with a 33% chance the unupped version will have an average reduction of 2 instead of 3.
The standard deviation will be Sqrt(number coins * success chance * (1 - success chance))
You can use wolfram alpha to generate the table using: BinomialDistribution[6,.5]

[russianspy1234]

bell distribution isnt random enough, this is an entropy card after all. i think ill leave it with completely random damage reduction,  id like it to be a bit better than diamond shield on average, currently its 4.5 reduction on average for 6 compared with diamonds 3.  that might be a bit much...  think ill drop 8 off to make it 3.5 for 6. the unupped averages at 3 so its equal to diamond shield, which is an upped card, but the randomness i feel brings it in line.

[OdinVanguard]

Should be fun.

[Xenocidius]

CURATOR COMMENT

• The Series field should either contain a link to a series topic or be left blank.

[freemod1espilon]

Just my two  , but I would say the unupped should be reduced to 4  to put it in line with the  equivalent. I would also suggest the following probabilities. Based on a bell shaped distribution, e.g. each potential point of reduction treated as a coin flip with a 50% chance of success. The upped version was made using a 7 coins and automatic +1 reduction.

Unupped 0 -> 1.56% 1 -> 9.38% 2 -> 23.44% 3 -> 31.25% 4 -> 23.44% 5 -> 9.38% 6 -> 1.56%

Upped 1 -> 0.78% 2 -> 5.47% 3 -> 16.41% 4 -> 27.34% 5 -> 27.34% 6 -> 16.41% 7 -> 5.47% 8 -> 0.78%

This can easily be adjusted to set the average to any value in the range by adjusting the success rate (like a loaded coin). I.e. with a 33% chance the unupped version will have an average reduction of 2 instead of 3.
The standard deviation will be Sqrt(number coins * success chance * (1 - success chance))
You can use wolfram alpha to generate the table using: BinomialDistribution[6,.5]

thats kind of parabolic isn't it,        Mathematical and yet still chaotic i'd love to see it in the game